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Begin with the coefﬁcients: 11 ÷ 11 = 1. Carry the bases (x and y) from the dividend into the answer. The divisor has a base (z) that is not in the dividend, so next, carry it into the answer. Change its exponent from 2 to –2. Because x does not appear in the divisor, carry its exponent into the answer. Finally, subtract the exponent of y in the divisor from the exponent of y in the dividend: 5 – 5 = 0, so our answer does not have a base of y after all. (11x3y5)(11y5z2) = x3z–2. 5. Begin with the coefﬁcients: –42 ÷ 6 = –7.

Because x does not appear in the divisor, carry its exponent into the answer. Finally, subtract the exponent of y in the divisor from the exponent of y in the dividend: 5 – 5 = 0, so our answer does not have a base of y after all. (11x3y5)(11y5z2) = x3z–2. 5. Begin with the coefﬁcients: –42 ÷ 6 = –7. Carry the bases (m, n, and o) from the dividend into the answer. Because o does not appear in the divisor, carry its exponent into the answer. Next, subtract the exponent of m in the divisor from the exponent of m in the dividend: 2 – 1 = 1.

WHEN WE ADD two whole numbers or subtract one whole number from another, we only have to work with one sign, either a plus sign or a minus sign. Integers are all of the whole numbers, their negatives, and zero. When we add two integers, we often have to work with two or more signs. Sometimes in an integer addition or subtraction problem, two signs appear right next to each other: 2 + –3. qxd:JSB 30 12/18/08 11:45 AM Page 30 algebra basics In other words, if the two signs are different, replace them with the minus sign.